(n^2-1)/(n^2+2)=0.28

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Solution for (n^2-1)/(n^2+2)=0.28 equation: 



(n^2-1)/(n^2+2)=0.28

We move all terms to the left:

(n^2-1)/(n^2+2)-(0.28)=0



Domain of the equation: (n^2+2)!=0

We move all terms containing n to the left, all other terms to the right

n^2!=-2

n^2!=-2/

n^2!=√-1/0

n!=NAN

n∈R



We add all the numbers together, and all the variables

(n^2-1)/(n^2+2)-0.28=0

We multiply all the terms by the denominator


(n^2-1)-(0.28)*(n^2+2)=0

We get rid of parentheses

n^2-(0.28)*(n^2+2)-1=0

We move all terms containing n to the left, all other terms to the right

n^2-(0.28)*(n^2+2)=1

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